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八年级数学秋季学期期中考试江苏教育版

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八年级数学秋季学期期中考试

八年级数学

110

1118

19

20

21

22

23

24

附加题

说明:1.可以使用计算器,但未注明精确度的计算问题不得采取近似计算,建议根据题型特点把握好使用计算器的时机.

2.本试卷满分120分,在120分钟内完成.相信你一定会有出色的表现!

评卷人

 

一、填空题:本大题共10小题;每小题2分,共20分.请将答案填写在题中的横线上.

1化简:         

2比较大小:      用“>”或“<”填空

3对398.15取近似值,精确到十分位是     

4如图的格点三角形ABC    三角形

5在△ABC中,∠A=60°,∠B     时,△ABC是等边三角形

6在△ABC中,∠C=90°,若AB=13 cmBC=5 cm,则AC      cm

7是从镜子中看到的一串数字,这串数字应为     

8如图,在△ABC中,∠C=90°,AD平分∠BAC,若

CD=6 cm,则点DAB的距离是       cm

9如图,等腰梯形ABCD中,ADBCAD=3AB=6BC=8.

DEAB,则△DEC的周长是     

10如图,△ABC是等腰直角三角形,D是斜边BC上的中点,

ABD绕点A旋转到△ACE的位置,恰好与△ACD组成正方

ADCE,则△ABD   时针方向旋转了     

评卷人

 

二、选择题:本大题共8小题;每小题3分,共24分.在每小题给出的四个选项中,只有一项是正确的,请将正确答案前的字母填入题后的括号内.每小题选对得3分,选错,不选或多选均得零分.

11近似数2.023的有效数字是····································································································   ).

   A1         B2         C3         D4

12····························································································································································· 的平方根是      ).

   A±12        B12          C)-12        D±

13····························································································································································· 下列各数组中,不是勾股数的是·····························································································································································   ).

   A)5,12,13                    B)7,24,25   

   C)8,12,15                    D)3k,4k,5kk为正整数)

14····························································································································································· 用刻度尺分别画下列图形的对称轴可以不用刻度尺上的刻度画的是····························································································   ).

   A①④        B②③        C③④        D①②

15····························································································································································· 在4,3.5,π五个数中,无理数有··············································································································································   ).

   A1         B2         C3         D4

16某数的平方根等于它的立方根,则这个数···································································   ).

   A1           B)-1         C0           D以上都不对

17····························································································································································· 下列条件中,能说明四边形ABCD是平行四边形的是··························································································································   ).

   AA=30°,∠B=150°,∠C=30°,∠D=150°

   BA=60°,∠B=60°,∠C=120°,∠D=120°

   CA=60°,∠B=90°,∠C=60°,∠D=150°

   DA=60°,∠B=70°,∠C=110°,∠D=120°

18····························································································································································· 下列说法中,正确的是     ).

   A在成中心时称的图形中,连结对称点的线段不一定都经过对称中心

   B在成中心对称的图形中,连结对称点的线段都被对称中心平分

   C若两个图形的对应点连成的线段都经过某一点.那么这两个图形一定关于这一点成中心对称

   D以上说法都正确


三、解答题:本大题共6小题,共76分.解答应写出文字说明或演算步骤.

得分

评卷人

19.(本小题满分16分)

计算:12(精确到百分位);

2π(保留2个有效数字).


得分

评卷人

20.(本小题满分12分)

如图,一个长方形的运动场,有一个球落到了点C,小明要从点A走到点C捡球,至少要走多少米?


21.(本小题满分12分)

得分

评卷人

在5×7的方格纸上,任意选出5个小方块,涂上颜色,使着色图形为轴对称图形,并画出其对称轴(要求:着色出一个图形,并画出一条对称轴即可).


得分

评卷人

22.(本小题满分12

ABC的边AB绕点B旋转到图中BA′的位置,点A′是A的对应点,画出ABC绕点B旋转后的图形.



23.(本小题满分12分)

得分

评卷人

如图,在△ABC中,ABAC,∠ABD=∠ACEBDCE相交于点O,猜想:BOCO成立吗?并说明理由.

得分

评卷人

24.(本小题满分12分)

现有一块等腰直角三角形木板,你能通过剪切,使它成为一个含有45°角的平行四边形吗?请你设计一个最简的方案,并说明你的方案的正确性.



附加题.(本小题满分10分)

得分

评卷人

请你把上面的解答再认真地检查一遍,别留下什么遗憾,并估算一下成绩是否达到了80分,如果你的全卷得分低于80分,则本题的得分将计入全卷总分,但计入后全卷总分最多不超过80分;如果你全卷得分已经达到或超过80分,则本题的得分不计入全卷总分.

求下列各式中x的值:

(1x2

(2x30.125


八年级数学参考答案及评分标准

一、填空题:(每小题2分,共20分)

11,2;2<;3398.2;4等腰;560°;6.12; 781007;86

917;10逆,90°或填顺,270°.

二、选择题:(每小题3分,共24分)

题号

11

12

13

14

15

16

17

18

答案

D

D

C

A

B

C

A

B

三、解答题:

19.解:(12=2+1.4141.732·············································································· 4

≈1.68;······································································································ 8

(2+π=2.24+3.14·········································································································· 4

≈5.4.······················································································································ 8

20.解:连结AC,在ABC中,由勾股定理得

AC2AB2BC2····························································································································· 4

=302+402································································································································ 6

=2500.···································································································································· 8

AC=50.··················································································································· 10

答:小明至少要走50米.··································································································· 12

21.解:图形有多种,如:

(每个图各4分)


22.解:如右图.······································ 12


23.解:成立.

在△ABC中,因为ABAC,所以∠ACB=∠ABC.··············································· 4

理由是:等边对等角.············································································································ 6

因为∠ABD=∠ACE,所以∠OBC=∠OCB.····························································· 8

在△OBC中,因为∠OBC=∠OCB,所以OBOC.··········································· 10

理由是:等角对等边.·········································································································· 12

24.解:作等腰直角三角形底边上的中线CD,交AB于点D,将等腰ABC分成两个全等的等腰直角三角形,如图翻折其中一个三角形使得DCCD重叠就可得到一个含有45°角的.· 4

因为CD是等腰ABC底边上的中线,

所以ADBD,即ADCB′.

又因为ABC是等腰

所以∠A=45°,ACCB,即ACDB′.

所以四边形ACBD,是一个含有45°角的平行四边形.

理由是:有两组对边相等的四边形是平行四边形.·············································· 12

附加题.(1)因为,········································································································· 3

所以x=±;···················································································································· 5

(2)因为(-0.53=-0.125,·························································································· 3

所以x=-0.5.··················································································································· 5