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八年级数学轴对称图形单元测试卷

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八年级数学

(测试内容:第一章 轴对称图形)

班别       座号       姓名           成绩­     

说明:1.可以使用计算器,但未注明精确度的计算问题不得采取近似计算,建议根据题型特点把握好使用计算器的时机.

2.本试卷满分100分,在90分钟内完成.相信你一定会有出色的表现!

一、填空题:本大题共10小题;每小题3分,共30分.请将答案填写在题中的横线上.

1如果两个图形关于某一条直线对称,那么连结对称点的线段被________________垂直平分.

2.如图,是一个轴对称图形,对称轴为直线l.图中ADE关于直线l的对称点分别是___________,图中长度相等的线段是_____________________ ________________________________________.

3到线段的两个端点的距离相等的点有_______个,一条线段的垂直平分线有_________条.

4如果一个等腰三角形的一个外角等于40°,则该等腰三角形的底角的度数是     

5等边三角形ABC中,ADBC上的高,则∠BAD     

6等边三角形的两条高线相交所成的钝角的度数是     

7在镜中看到的一串数字是“”,则这串数字是     

8如图,ABAC,∠1=∠2BD3cm,那么BC的长为   cm

9如图,等边三角形ABC的三条中线交于点O.图中除△ABC

有____________________________________________是等腰三角形

10如图,在等腰梯形ABCD中,对角线ACBD交于点O,图中全等的三角形是                    


二、选择题:本大题共8小题;每小题3分,共24分.在每小题给出的四个选项中,只有一项是正确的,请将正确答案前的字母填入题后的括号内.每小题选对得3分,选错,不选或多选均得零分.

11····························································································································································· 下列是我国四大银行的商标,其中不是轴对称图形的·····················································································································   ).


   A            B            C            D

12····························································································································································· 下列图形不一定是轴对称图形的是·····························································································································································   ).

   A线段        B正方形      C半圆        D三角形

13····························································································································································· 正五角星的对称轴有   ).

   A)1条         B)2条         C)5条         D)10

14····························································································································································· 已知△ABC的周长为24ABACADBCD,若△ABD的周长为20,则AD的长为····················································   ).

   A6           B8           C10          D12

15····························································································································································· 已知等腰三角形的一边等于3,一边等于6,那么它的周长等于········································································································   ).

   A)12          B)12或15      C)15          D)15或18

16····························································································································································· 已知等腰三角形的周长为24,腰长为x,则x的取值范围是···············································································································   ).

   Ax>12       Bx<6        C)6x<12     D)0x<12

17·············································································································· 如图,等边三角形ABC中,ADBC上的高,取AC的中点E,连结DE,则图中与DE相等的线段有·····················   ).

   A)1条              B)2

   C)3条              D)4

18·············································································································· 如图,在△ABC中,点O是∠ABC的平分线与线段BC的垂直平分线的交点,则下列结论不一定成立的是··········   ).

   AOBOC           BODOF

   COAOBOC      DBDDC


三、解答题:本大题共4小题,共46分.解答应写出文字说明或演算步骤.

19.(10分)(1)请仔细观察图形(阴影部分),指出所给虚线中哪些是图形的对称轴?

2)下列图形是轴对称图形吗?如果是,分别画出它们的对称轴.

20.(12分)(1)在数学课上,老师提出了一个问题:“角是轴对称图形吗?如果是,那么它的对称轴是什么?”小明同学马上举手回答:“角是轴对称图形,角平分线就是它的对称轴.”同学们,小明同学的回答有正确吗?为什么?

(2)如图,在△中,∠C=90°,用刻度尺及量角器分别作出ACBC边的垂直平分线,并说明它们的交点与斜边AB的关系.


21.(12分)(1如图,已知AD是线段BC的垂直平分线,且BD=3cm,△ABC的周长为20cm,求AC的长.


(2)如图,在ABC中,ABACADBCBAD=40°,ADAE.求CDE的度数.

22.(12分)已知:如图,在等腰梯形ABCD中,ADBCACBD,垂足为OAC8cm.求梯形ABCD的面积.


八年级数学参考答案

一、填空题:(每小题3分,共30分)

1对称轴;2BCECEDE,CFDF,ACBD,AFBF3.无数,且只有1420°

5.30°6.120°7.309087869AOB、△AOC、△BOC10ABC≌△DCB、△ABD≌△DCA、△ABO≌△DCO

二、选择题:(每小题3分,共24分)

题号

11

12

13

14

15

16

17

18

答案

A

D

C

B

C

C

D

C

三、解答题:

19.解:(1d;(2)都是轴对称图形,作图略.

20.解:(1有错误的地方,错误出现在“角平分线就是角的对称轴”因为对称轴是一条直线,而角平分线是一条射线.对称轴应该说是角平分线所在的直线

2)作图略,ACBC边的垂直平分线的交点恰好是斜边AB的中点.

21.解:(17cm220°

22.解:32cm2.

提示:梯形ABCD的面积=△ACD和面积+△ACB的面积

×AC×OD×AC×OB

×AC×(ODOB

×AC×DB32cm2

或将对角线AC平移到DE,交BC的延长线于E,于是得△DCE≌△BAD,所以△BDE的面积等于梯形ABCD的面积.