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初中毕业生学业考试数学试卷

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初中毕业生学业考试数学试卷

说明:全卷共8页,考试时间90分钟,满分120分.

题号

总分

16

17

18

19

20

21

22

23

24

25

得分

一、选择题:每小题3分,共15分;每小题给出四个答案,其中有一个是正确的,把所选答案的编号填写在题目后面的括号内.

1.等于(  )

A.2          B.        C.           D.

2.小明在镜中看到身后墙上的时钟,实际时间最接近8时的是下图中的(  )


3.我市大部分地区今年5月中、下旬的天气情况是:前5天小雨,后5天暴雨.那么能反映我市主要河流水位变化情况的图象大致是(  )


4.如图1,把矩形沿对折,若,则等于(  )

A.              B.      

C.              D.

5.在同一平面直角坐标系中,直线与双曲线的交点个数为(  )

A.0个        B.1个        C.2个        D.无法确定

二、填空题:每小题3分,共30分;答案填写在该题的横线上.

6.我市约有495万人口,用科学记数法表示为          人.

7.如果一个几何体的主视图是等腰三角形,那么这个几何体可以是         .(填上满足条件的一个几何体即可)

8.一个袋中装有6个红球、4个黑球、2个白球,每个球除颜色外完全相同,从袋中任意摸出一个球,那么摸出       球的可能性最大.

9.计算:       

10.计算:      

11.将抛物向左平移1个单位后,得到的抛物线的解析式是    

12.当        时,分式的值为零.

13.能使平行四边形为正方形的条件是         .(填上一个符合题目要求的条件即可)

14.如图2,两个半圆中,小圆的圆心在大的直径上,

长为4的弦与直径平行且与小半圆相切,那么圆中阴影部

分面积等于       

15.如图3,已知的周长为,分别连接

的中点,再连接的中点

,再连接的中点

,这样延续下去,最后得

的周长为的周长为的周长为的周长为,则          

三、解答题:本大题有10小题,共75分.

16.本小题满分6分.

因式分解:

17.本小题满分6分.

解不等式组:

18.本小题满分6分.

如图4是某文具店在2005年卖出供学生使用的甲、乙、丙三种品牌科学计算器个数的条形统计图,试解答下面问题:

(1)求卖出甲、乙、丙三种科学计算器的个数的频率;

(2)根据以上统计结果,请你为该文具店进货提出一条合理化建议.


19.本小题满分6分.

如图5,已知的顶点的坐标分别是

(1)作出关于原点中心对称的图形;

(2)将绕原点按顺时针方向旋转后得到,画出,并写出点的坐标.

20.本小题满分7分.

小明与小华在玩一个掷飞镖游戏,如图甲是一个把两个同心圆平均分成8份的靶,当飞镖掷中阴影部分时,小明胜,否则小华胜(没有掷中靶或掷到边界线时重掷).

(1)不考虑其他因素,你认为这个游戏公平吗?说明理由.

(2)请你在图乙中,设计一个不同于图甲的方案,使游戏双方公平.


                                                

21.本小题满分7分.

梅华中学九年级数学课外学习小组某下午实践活动课时,测量朝西教学楼前的旗杆的高度.如图7,当阳光从正西方向照射过来时,旗杆的顶端的影子落在教学楼前的坪地处,测得影长与地面的夹角.在同一时刻,测得一根长为1m的直立竹竿的影长恰为4m.根据这些数据求旗杆的高度.(可能用到的数据:,结果保留两个有效数字)

D

22.本小题满分8分.

某公司开发生产的1200件新产品需要精加工后才能投放市场,现有甲、乙两个工厂都想加工这批产品.公司派出相关人员分别到这两间工厂了解生产情况,获得如下信息:

信息一:甲工厂单独加工完成这批产品比乙工厂单独加工完成这批产品多用10天;

信息二:乙工厂每天比甲工厂多加工20件.

根据以上信息,求甲、乙两个工厂每天分别能加工多少件新产品?

23.本小题满分8分.

用两个全等的正方形拼成一个矩形,把一个足够大的直角三角尺的直角顶点与这个矩形的边的中点重合,且将直角三角尺绕点按逆时针方向旋转.

(1)当直角三角尺的两直角边分别与矩形的两边相交于点时,如图甲,通过观察或测量的长度,你能得到什么结论?并证明你的结论.

(2)当直角三角尺的两直角边分别与的延长线,的延长线相交于点时(如图乙),你在图甲中得到的结论还成立吗?简要说明理由.

24.本小题满分10分.

如图9,直线的解析式为轴,轴分别交于点

(1)求原点到直线的距离;

(2)有一个半径为1的从坐标原点出发,以每秒1个单位长的速度沿轴正方向运动,设运动时间为(秒).当与直线相切时,求的值.

25.本小题满分11分.

如图10,点在抛物线上,过点作与轴平行的直线交抛物线于点,延长分别与抛物线相交于点,连接,设点的横坐标为,且

(1)当时,求点的坐标;

(2)当为何值时,四边形的两条对角线互相垂直;

(3)猜想线段之间的数量关系,并证明你的结论.


初中毕业生学业考试

数学试卷参考答案及评分意见

一、选择题:每小题3分,共15

1.D       2.B       3.B       4.A       5.C

二、填空题:每小题3分,共30

6.;  7.圆锥或正三棱锥或正四棱锥;   8.红; 9.3    10.

11.; 12.; 13.等;

14.;   15.

三、解答下列各题:共75

16.解:原式············································································· 2分

      ····················································································· 4分

      ············································································· 6分

17.解:由,得,······································································· 2分

    由,得,·············································································· 4分

    原不等式组的解集是:.····························································· 6分

18.解:(1)卖出甲计算器个数的频率:········································ 2分

       卖出乙计算器个数的频率:········································· 3分

       卖出丙计算器个数的频率:.····································· 4分

  (2),·············································································· 5分

    该文具店进甲、乙、丙三种科学计算器时,按的比例进货.············· 6分

    (或该文具店进货时,丙科学计算器进多一些,而甲、乙科学计算器进少一些.类  似这样的合理答案5分)

19.(1)正确画出图形·········································································· 3分

  (2)正确画出图形·········································································· 5分

  ························································································ 6分

20.解:(1)这个游戏公平.······························································· 2分

  根据图甲的对称性,阴影部分的面积等于圆面积的一半,

  这个游戏公平.·································································································· 4分

(2)把图乙中的同心圆平均分成偶数等分,再把其中的一半作为阴影部分即可.(图略)   7分

21.解:如图,过点分别作于点的延长线于.······· 1分

  在中,

  

  ,··································································· 2分

m··········································· 3分

  又········································································································· 5分

  

      .···································································· 6分

  .··············································································· 7分

22.解:设甲工厂每天能加工件新产品,··································································· 1分

  则乙工厂每天能加工件新产品.······························································· 2分

  依题意得方程 .····································································· 4分

  解得(不合题意舍去),····························································· 6分

  经检验是所列方程的解,

  .····································································································· 7分

  答:甲工厂每天能加工40件新产品,乙工厂每天能加工60件新产品.·················· 8分

23.解:(1).···························································································· 2分

  四边形都是正方形,

  

  ,·················· 3分

  

  ,······································································································· 4分

  .··················································································· 5分

(2)结论仍然成立.··················································································· 6分

  同理可证

  .······························································ 8分

24.解:(1)在中,令,得,得

  令,得,得

  .····················································· 2分

  设点到直线的距离为

  

  .·························································································· 4分

  (其它解法参照给分)

(2)如图,设与直线相切于点,连,则,······························· 5分

  

  

  ······································································· 6分

  由(1)得

  

  (秒).···························································································· 8分

  根据对称性得

  (秒).························································· 9分

  与直线相切时,秒或秒.······················································· 10分

25.解:(1)在抛物线上,且,······················· 1分

  与点关于轴对称,.························································ 2分

  设直线的解析式为

  .······················································································· 3分

  解方程组,得.································································· 4分

(2)当四边形的两对角线互相垂直时,由对称性得直线轴的夹角等于所以点的纵、横坐标相等,···························································································································· 5分

  这时,设,代入,得

  即当时,四边形的两条对角线互相垂直.········································· 7分

(3)线段.································································································ 8分

  在抛物线,且

  得直线的解析式为

  解方程组,得点······················································· 9分

  由对称性得点,················································· 10分

  

  .···································································································· 11分