当前位置:首页 -初中数学试卷 - 初中三年级数学试题 - 正文*

初中毕业生学业考试数学试题

2014-5-11 0:17:36下载本试卷

初中毕业生学业考试数学试题

注意事项:

1.本试题满分120分,考试时间为120分钟;

2.请考生在答题前,先将县(市)、学校、考号和姓名填写在试卷密封线内的矩形方框内;

3.答案一律用钢笔或圆珠笔,考生在考试过程中允许使用科学计算器.

题号

总分

得分

阅卷人

复查人

一、精心选一选(本大题共10小题,每小题都给出代号为A,B,C,D的四个选项,其中有且只有一个选项符合题目要求,把符合题目要求的选项的字母代号直接填在答题框内相应的题号下的方框中,不填、填错或一个方框内填写的代号超过一个,一律得0分;每小题3分,满分30分)

题号

1

2

3

4

5

6

7

8

9

10

答案

1.下列各式中,一定成立的是(  )

A.    B.  C.     D.

2.二元一次方程组的解是(  )

A.          B.        C.        D.

3.下列命题正确的是(  )

A.中,如果,那么;

B.如果,那么线段一定可以围成一个三角形;

C.三角形三边垂直平分线的交点有可能在一边上;

D.平分弦的直径垂直于弦

4.下列四个数据,精确的是(  )

A.小莉班上有人;                    B.某次地震中,伤亡万人;

C.小明测得数学书的长度为厘米;      D.吐鲁番盆地低于海平面大约

5.观察图甲,从左侧正对长方体看到的结果是图乙中的(  )


6.学校升旗仪式上,徐徐上升的国旗的高度与时间的关系可以用一幅图近似地刻画,这幅图是下图中的(  )


7.如图,将一张长方形纸片对折两次,然后剪下一个角,打开.如果要剪出一个正方形,那么剪口线与折痕成(  )

A.角          B.角    C.角          D.


8.如图所示,课堂上小亮站在座位上回答数学老师提出的问题,那么数学老师观察小亮身后,盲区是(  )

A.         B.四边形

C.          D.

9.如图,已知,增加下列条件:①;②;③;④.其中能使的条件有(  )

A.个         B.个        C.个           D.

10.在中,是边上一点(不与点重合),过点作直线与另一边相交,使所得的三角形与原三角形相似,这样的直线有(  )

A.条          B.条           C.条        D.

二、耐心填一填(本大题共6小题,每小题3分,满分18分.把答案直接写在横线上)

11.已知直线经过第一、二、四象限,则其解析式可以为______________(写出一个即可).

12.用火柴棒按下图中的方式搭图形,按照这种方式搭下去,搭第个图形需____________根火柴棒.


13.学生小颖自制一个无底圆锥形纸帽,圆锥底面圆的半径为,母线长为,那么围成这个纸帽的面积(不计接缝)是_________(结果保留三个有效数字).

14.如图,已知,则___________.


15.如图,在平面直角坐标系中,请按下列要求分别作出变换后的图形(图中每个小正方形的边长为个单位):

(1)向右平移个单位;(2)关于轴对称;(3)绕点顺时针方向旋转

16.小亮调查本班同学的身高后,将数据绘制成如下图所示的频数分布直方图(每小组数据包含最小值,但不包含最大值.比如,第二小组数据满足:,其它小组的数据类似).设班上学生身高的平均数为,则的取值范围是___________________.


三、细心做一做(本大题共3小题,满分18分)

17.(5分)计算:(至少要有两步运算过程).

18.(5分)化简:

19.(8分)小莉和小慧用如图所示的两个转盘做游戏,转动两个转盘各一次,若两次数字和为奇数,则小莉胜;若两次数字和为偶数,则小慧胜.这个游戏对双方公平吗?试用列表法或树状图加以分析.

四、静心试一试(本大题共4小题,满分24分)

20.(6分)某校科技小组进行野外考察,途中遇到一片十几米宽的烂泥湿地.为了安全、迅速通过这片湿地,他们沿着前进路线铺了若干块木块,构筑成一条临时近道.木板对地面的压强是木板面积的反比例函数,其图象如下图所示.

(1)请直接写出这一函数表达式和自变量取值范围;

(2)当木板面积为时,压强是多少?

(3)如果要求压强不超过,木板的面积至少要多大?


21.(6分)武当山风景管理区,为提高游客到某景点的安全性,决定将到达该景点的步行台阶进行改善,把倾角由减至,已知原台阶的长为米(所在地面为水平面).

(1)改善后的台阶会加长多少?(精确到米)

(2)改善后的台阶多占多长一段地面?(精确到米)

22.(6分)市“康智”牛奶乳业有限公司经过市场调研,决定从明年起对甲、乙两种产品实行“限产压库”,要求这两种产品全年共新增产量件,这件的总产值(万元)满足:.已知有关数据如下表所示,那么该公司明年应怎样安排新增产品的产量?

产品

每件产品的产值

万元

万元

23.(6分)如图甲,李叔叔想要检测雕塑底座正面四边形是否为矩形,但他随身只带了有刻度的卷尺,请你设计一种方案,帮助李叔叔检测四边形是否为矩形(图乙供设计备用).

五、用心想一想(本大题共2小题,满分18分)

24.(8分)如图,的直径,

(1)求证:,并求的长;

(2)延长,使,连接,那么直线相切吗?为什么?


25.(10分)市“健益”超市购进一批元/千克的绿色食品,如果以元/千克销售,那么每天可售出千克.由销售经验知,每天销售量(千克)与销售单价(元)()存在如下图所示的一次函数关系.

(1)试求出的函数关系式;

(2)设“健益”超市销售该绿色食品每天获得利润元,当销售单价为何值时,每天可获得最大利润?最大利润是多少?

(3)根据市场调查,该绿色食品每天可获利润不超过元,现该超市经理要求每天利润不得低于元,请你帮助该超市确定绿色食品销售单价的范围(直接写出).


六、综合运用(本题满分12分)

26.已知抛物线为常数,且)的顶点为,与轴交于点;抛物线与抛物线关于轴对称,其顶点为,连接

注:抛物线的顶点坐标为

(1)请在横线上直接写出抛物线的解析式:________________________;

(2)当时,判定的形状,并说明理由;

 
(3)抛物线上是否存在点,使得四边形为菱形?如果存在,请求出的值;如果不存在,请说明理由.

 

 


初中毕业生学业考试

数学试题参考答案及评分说明

一、选择题

1.A  2.D  3.C  4.A  5.B  6.A  7.C  8.D

9.B  10.C

二、填空题

11.如:(答案不唯一)  12.  13.  14.

15.每个图形1分,图形略      16.

说明:11~16题凡等价结果均给满分.

三、解答题

17.解:原式    ····································· 3分

      .·············································· 5分

18.解:原式  ····························· 2分

      .   ····················································· 5分

19.解:这个游戏对双方公平.  ······························································ 1分

理由如下:

                 ···················································· 6分

从表中可以看出,总共有种结果,每种结果出现的可能性相同,而两数和为奇数的结果有种.    7分

.因此,这个游戏对双方公平.  ···································· 8分

20.解:(1)(解析式与自变量取值范围各1分).  ······ 2分

(2)当时,

即压强是.  ················································································ 4分

(3)由题意知,

即木板面积至少要有.  ·································································· 6分

21.解:(1)如图,在中,

.  ················································· 1分

中,

即改善后的台阶会加长米.  ····························································· 3分

(2)如图,在中,

.  ················································ 4分

中,

即改善后的台阶多占米长的一段地面.  ············································ 6分

22.解:设该公司安排生产新增甲产品件,那么生产新增乙产品件,由题意,

,  ······················································· 2分

解这个不等式组,得,  ························································· 3分

依题意,得.  ······································································ 4分

时,;当时,;当时,

    ········································································································ 5分

所以该公司明年可安排生产新增甲产品件,乙产品件;或生产新增甲产品件,

乙产品件;或生产新增甲产品件,乙产品件.  ······························ 6分

23.解:方案如下:

①用卷尺分别比较的长度,当,且时,四边形为平行四边形;否则四边形不是平行四边形,从而不是矩形.

      ································································································· 3分

②当四边形是平行四边形时,用卷尺比较对角线的长度.当时,四边形是矩形;否则四边形不是矩形.  ······································································· 6分

说明:(1)考生设计以下方案,请参照给分.

方案一:先用勾股定理逆定理测量一个角是否为直角,然后用同样的方法再测量另外两个角是否也为直角,并给出判断;

方案二:先测量四边形是否为平行四边形,再用勾股定理逆定理测量其中一个角是否为直角,并给出判断.

(2)设计方案中如果没有从反面说明四边形不是矩形,扣2分.

24.(1)证明:

.  ·································· 3分

.  ······················································································· 5分

(2)直线相切.  ···································································· 6分

理由如下:

连接

的直径,

直线相切.  ········································································· 8分

25.解:(1)设,由图象可知,

  ····················································································· 2分

解之,得

,不写自变量取值范围不扣分).············ 4分

(2).·· 6分

有最大值.

时,

即当销售单价为元/千克时,每天可获得最大利润元.···················· 8分

(3).(写对一个得1分)······························· 10分

26.(1).  ································································ 2分

(2)当时,为等腰直角三角形.  ······································ 3分

理由如下:

如图:与点关于轴对称,点又在轴上,

.  ························································································ 4分

过点作抛物线的对称轴交轴于,过点

时,顶点的坐标为

的坐标为

从而

由对称性知

为等腰直角三角形.  ································································ 7分

(3)假设抛物线上存在点,使得四边形为菱形,则

由(2)知,

从而为等边三角形.  ··································································· 8分

四边形为菱形,且点上,与点关于对称.

的交点也为点,因此

的坐标分别为

中,

故抛物线上存在点,使得四边形为菱形,此时

   ············································································································ 12分

说明:只求出的一个值扣2分.