高中阶段学校招生考试数学试卷课改实验区
说明:全卷共8页,考试时间90分,满分150分.
一、选择题(每小题3分,共36分,每小题给出4个答案,其中只有一个正确,把所选答案的编号写在题目后面的括号内)
1.的相反数是( )
A. B.
C.
D.
2.今年我市参加中考的人数约是,数据
用科学记数法表示为( )
A. B.
C.
D.
3.在下列长度的四根木棒中,能与3cm,7cm两根木棒围成一个三角形的是( )
A.7cm B.4cm C.3cm D.10cm
4.下列运算正确的是( )
A. B.
C.
D.
5.点关于
轴对称的点的坐标是( )
A. B.
C.
D.
6.下图中所示的几何体的主视图是( )
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7.下列事件是必然事件的是( )
A.今年10月1日湛江的天气一定是晴天
B.2008年奥运会刘翔一定能夺得110米跨栏冠军
C.当室外温度低于℃时,将一碗清水放在室外会结冰
D.打开电视,正在播广告
8.图1是
两国2005年财政经费支出情况的扇形统计图.根据统计图,下面对两国全年教育经费支出判断正确的是( )
A.国比
国多
B.国比
国多
C.国与
国一样多
D.无法确定哪国多
9.数据12,10,13,8,17,10,21的中位数是( )
A.8 B.10 C.13 D.12
10.在一个不透明的口袋中,有大小、形状完全相同,颜色不同的球15个,从中摸出红球的概率为,则袋中红球的个数为( )
A.10 B.15 C.5 D.3
11.小颖从家出发,直走了20分钟,到一个离家1000米的图书室,看了40分钟的书后,用15分钟返回到家,下图中表示小颖离家时间与距离之间的关系的是( )
12.如图2,
的半径为5,弦
的长为8,点
在线段
(包括端点
)上移动,则
的取值范围是( )
A.
B.
C.
D.
二、填空题(每小题3分,共24分,请把答案填在横线上)
13.分解因式: .
14.请写出一个图象位于第二、四象限的反比例函数: .
15.数据100,99,99,100,102,100的方差 .
16.如图3,已知直线,
,
,则
度.
17.图4是平面镜里看到背向墙壁的电子钟示数,这时的实际时间应该是 .
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18.下面是一个简单的数值运算程序,当输入的值为2时,输出的数值是 .
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19.如果一个扇形的圆心角为,半径为
,那么该扇形的弧长是 .
20.观察下列顺序排列的等式:,….试猜想第
个等式(
为正整数):
.
三、解答题(每小题6分,共30分)
21.计算:.
22.先化简,再求值:,其中
.
23.如图5,请你画出方格纸中的图形关于点的中心对称图形,并写出整个图形的对称轴的条数.
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24.近年来,我市开展以“四通五改六进村”为载体,以生态文明为主要特色的新农村建设活动取得了明显成效.下面是市委领导和市民的一段对话,请你根据对话内容,替市领导回答市民提出的问题(结果精确到0.1%).
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领导
市民
25.如图6,点分别为四边形
的边
的中点,试判断四边形
的形状,并证明你的结论.
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四、解答题(每小题9分,共36分)
26.小刘同学为了测量雷州市三元塔的高度,如图7,她先在处测得塔顶
的仰角为
,再向塔的方向直行35米到达
处,又测得塔顶
的仰角为
,请你帮助小刘计算出三元塔的高度(小刘的身高忽略不计,结果精确到1米).
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27.为了让学生了解安全知识,增强安全意识,我市某中学举行了一次“安全知识竞赛”.为了了解这次竞赛成绩情况,从中抽取了部分学生的成绩(得分取整数,满分为100分)为样本,绘制成绩统计图,如图8所示,请结合统计图回答下列问题:
(1)本次测试的样本容量是多少?
(2)分数在80.5~90.5这一组的频率是多少?
(3)若这次测试成绩80分以上(含80分)为优秀,则优秀人数不少于多少人?
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28.某工厂现有甲种原料280kg,乙种原料190kg,计划用这两种原料生产两种产品50件,已知生产一件
产品需甲种原料7kg、乙种原料3kg,可获利400元;生产一件
产品需甲种原料3kg,乙种原料 5kg,可获利350元.
(1)请问工厂有哪几种生产方案?
(2)选择哪种方案可获利最大,最大利润是多少?
29.如图9,是
的直径,
平分
,交
于点
,过点
作直线
,交
的延长线于点
,交
的延长线于点
.
(1)求证:是
的切线;
(2)若
,
,求
的长.
五、解答题(每小题12分,共24分)
30.如图10,在中,
,
,把边长分别为
的
个正方形依次放入
中,请回答下列问题:
(1)按要求填表
| 1 | 2 | 3 |
|
(2)第个正方形的边长
;
(3)若是正整数,且
,试判断
的关系.
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31.已知抛物线与
轴相交于点
,
,且
是方程
的两个实数根,点
为抛物线与
轴的交点.
(1)求的值;
(2)分别求出直线和
的解析式;
(3)若动直线与线段
分别相交于
两点,则在
轴上是否存在点
,使得
为等腰直角三角形?若存在,求出点
的坐标;若不存在,说明理由.
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高中阶段学校招生考试数学试题课改实验区
参考答案及评分标准
一、选择题(每小题3分,共36分)
题号 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 |
答案 | B | C | A | B | D | D | C | D | D | C | A | A |
二、填空题(每小题3分,共24分)
13. 14.
等 15.1 16.80 17.
18.1 19. 20.
三、解答题(每小题6分,共30分)
21.解:原式··························································································· 4分
.······································································································ 6分
22.解:原式························································································· 2分
······························································································ 3分
··································································································· 4分
当时,原式
························································································ 5分
························································································· 6分
23.解:如图1,·········································································································· 4分
共有4条对称轴.········································································································· 6分
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24.解:设平均每年生态文明村增长率是,根据题意,得·········································· 1分
····················································································· 3分
解得:(不合题意,舍去)·················································· 5分
答:平均每年生态文明村增长率约是18.1%.································································ 6分
25.解:四边形是平行四边形··········································································· 1分
证明:连结
,如图2.
分别是
的中点,
是
的中位线,……………………2分
,且
.………………3分
同理:,且
,…………4分
.……………………………………5分
四边形
是平行四边形.·················································································· 6分
26.解:在中,
.············································································································ 2分
在中,
.············································································································ 4分
,
,··························································································· 6分
(米)········································································ 8分
答:三元塔的高度约是34米.······················································································ 9分
27.解:(1),
本次测试的样本容量是100.····················································································· 3分
(2).
分数在80.5~90.5这一组的频率是0.52.···································································· 6分
(3),
优秀人数不少于75人.····························································································· 9分
28.解:(1)设生产产品
件,生产
产品
件,则······································· 1分
································································································· 2分
解得:.······························································································· 3分
为正整数,
可取30,31,32.
当时,
,
当时,
,
当时,
,·························································································· 4分
所以工厂可有三种生产方案,分别为:
方案一:生产产品30件,生产
产品20件;
方案二:生产产品31件,生产
产品19件;
方案三:生产产品32件,生产
产品18件;··························································· 5分
(2)方案一的利润为:元;
方案二的利润为:元;
方案三的利润为:元.······················································ 8分
因此选择方案三可获利最多,最大利润为19100元.····················································· 9分
29.(1)证明:连结,如图3.
平分
,
.……………………1分
,
,……………………2分
,
.……………………………3分
,
,
是
的切线.·································································································· 4分
(2)设是
的半径,
在中,
············································································ 5分
即.
解得.·················································································································· 6分
,
,
.·································································································· 7分
即.
解得.·························································································· 8分
.························································································ 9分
30.(1)········································································································ 6分
(2).················································································································ 8分
(3)
······················································································· 10分
.································································································· 11分
.······································································································· 12分
31.解:(1)由,得
.
,··································································································· 1分
把两点的坐标分别代入
联立求解,得
.······································································································ 2分
(2)由(1)可得,
当
时,
,
.
设,把
两点坐标分别代入
,联立求得
.
直线
的解析式为
.····················································· 3分
同理可求得直线的解析式是
.···························································· 4分
(3)假设存在满足条件的点,并设直线
与
轴的交点为
.
①当
为腰时,分别过点
作
轴于
,作
轴于
,如图4,则
和
都是等腰直角三角形,
,
.
,
,
,即
.
解得.················································································································ 6分
点
的纵坐标是
,
点
在直线
上,
,解得
,
.
,同理可求
.··············································································· 8分
②当为底边时,
过
的中点
作
轴于点
,如图5,
则,
由,
得,即
,
解得.…………………………………………9分
同1方法.求得,
,
.····························································· 11分
结合图形可知,,
,
是
,
也满足条件.
综上所述,满足条件的点共有3个,即
.················ 12分
说明:以上各题如有其他解(证)法,请酌情给分.